Question

please tell with process​

Answer 1

Question find the following angles ,

• Angle BCA , Angle DCE , Angle DEG , Angle CDE

Solution :

Firstly we can see that angle 130° + angle BAC form linear pair so ,

• 130 + angle BAC = 180
• Angle BAC = 180 - 130
• Angle BAC = 50

Now in triangle ABC by angle sum property ,

• 50 + 75 + Angle BCA = 180
• Angle BCA = 180 - 125
• Angle BCA = 55

We can see that Angle BCA is vertically opposite to Angle DCE So ,

• Angle BCA = Angle DCE = 55

Angle ABC and Angle CDE form alternate interior angles thus they are equal ,

• Angle CDE = Angle ABC = 75

Now by angle sum property in triangle CDE ,

• 55 + 75 + Angle DEC = 180
• Angle DEC = 180 - 130
• Angle DEC = 50

Angle DEC and Angle DEG form a linear pair thus ,

• Angle DEC + Angle DEG = 180
• 50 + Angle DEG = 180
• Angle DEG = 130

Answer 2

Step-by-step explanation:

BCA = 55

DEG = 115

CDE = 60

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