Physics, asked by suryanshumohansingh, 1 month ago

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Answered by jk882202
0

Answer:

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Explanation:

simple interest , S.I = Rs.1260 = 10O

PR X 2 = 50 PR

Compound interest C. I = A - P = P ( 1 + 100 R )

_P =PR ( R/ 10000 + 1/50 = RS. 1323

_ ii

Dividing (ii)÷(i)

200R + I = 1260 = I323

Rate,R = 10:% Pa

Now

100 P RT = 1260 = 10O

Px 10 x 2 = 1260

principal / P = R s 6,300

Answered by rajeevjnp
0

Answer:

hope it helps

Explanation:

Computation of compound interest by using growing principal becomes lengthy and complicated when the period is long. If the rate of interest is annual and the interest is compounded quarterly (i.e., 3 months or, 4 times in a year) then the number of years (n) is 4 times (i.e., made 4n) and the rate of annual interest (r) is one-fourth (i.e., made r4). In such cases we use the following formula for compound interest when the interest is calculated quarterly.

If the principal = P, rate of interest per unit time = r4%, number of units of time = 4n, the amount = A and the compound interest = CI

Then

A = P(1 + r4100)4n

Here, the rate percent is divided by 4 and the number of years is multiplied by 4.

Therefore, CI = A - P = P{(1 + r4100)4n - 1}

Note:

A = P(1 + r4100)4n is the relation among the four quantities P, r, n and A.

Given any three of these, the fourth can be found from this formula.

CI = A - P = P{(1 + r4100)4n - 1} is the relation among the four quantities P, r, n and CI.

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