Physics, asked by suryamohansingh07, 28 days ago

please tennetiraj86 please answer this I will Mark you brainlist​

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Answers

Answered by InsaanGamer
0

∆ABC ~ ∆ DEC

AB = 20 units

AC = 48 units

BC :EC = 2:3

To find :-

Find the length of DC?

Solution:-

Given that

∆ABC ~ ∆ DEC

We know that

If two triangles are said to be similar ,

If the corresponding angles are equal.

If he Corresponding sides are in the same ratio.

=> AB/DE = BC/EC = AC/DC ------(1)

Given that

AB = 20 units

AC = 48 units

BC :EC = 2:3

=> BC/EC = 2/3

On Substituting these values in (1) then

=> 20/DE = 2/3 = 48/DC

On taking 20/DE = 2/3

On applying cross multiplication then

=> DE×2 = 20×3

=> DE = 20×3/2

=> DE = 10×3

=> DE = 30 units

On taking 2/3 = 48/DC

=> (2/3)×DC = 48

=>DC = 48×(3/2)

=>DC = 24×3

=> DC = 72 units

or

20/30 = 48/DC

On applying cross multiplication then

=> DC×20 = 30×48

=> DC = 30×48/20

=> DC = 3×24

=> DC = 72 units

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