Math, asked by suryanshumohansingh, 2 months ago

please tennetiraj86 please answer this question please I will Mark you brainlist.​

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Answers

Answered by TigerMan28
0

Answer:

96

Step-by-step explanation:

As all sides of rhombus are equal.

A.T.Q.

3x - 6 = x + 14

3x - x = 14 + 6

2x = 20

x = 10

As, side is x + 14.

Side = x + 14

= 10 + 14

= 24

Perimeter = 4 × side

= 4 × 24

= 96

Plz mark me the brainliast.

Answered by tennetiraj86
2

Step-by-step explanation:

Given :-

Two consecutive sides of a rhombus are represented by 3x-6 and x+14

To find :-

Find the perimeter of the rhombus ?

Solution :-

Given that :

The consecutive sides of a rhombus are 3x-6 and x+14

In a rhombus all sides are equal

so given two sides are equal

3x-6 = x+14

=> 3x-x = 14+6

=> 2x = 20

=> x = 20/2

=> x = 10

the side = 3x-6 = 3(10)-6 = 30-6 = 24

So all sides are equal to 24 units each

So the value of side = 24units

perimeter of a rhombus = 4×side

=> P = 4×24

=> P = 96 units

Answer:-

The perimeter of the given rhombus is 96 units

Used formulae:-

  • All sides are equal in rhombus

  • Perimeter of a rhombus is 4×side

  • Perimeter of a polygon is the sum of all sides.
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