Question

please the question ​

Answer 1

Solution :

Given, x² + y² = 27xy

⇒ (x - y)² + 2xy = 27xy

⇒ (x - y)² = (27 - 2) xy

⇒ (x - y)² = 25xy

⇒ x - y = 5 (xy)¹'²

⇒ (x - y)/5 = (xy)¹'²

Taking log to both sides, we get

log{(x - y)/5} = log (xy)¹'²

⇒ log {(x - y)/5} = 1/2 * log(xy)

⇒ log {(x - y)/5} = 1/2 * (logx + logy)

Hence, proved.