Please these are the questions..please help me as soon as possible!
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Q25 ans=
dis= 10X4=40.
Q26 ans=acceleration.
dis= 10X4=40.
Q26 ans=acceleration.
Anonymous:
Are u sure..??
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Ans 25) distance travelled can be taken out by the area under the velocity time graph
therefore, distance = 1/2×10×4 = 20m
Ans 26) AB shows that its acceleration is positively increading , BC shows that its acceleration is now constant and AD shows that its acceleration is 0.
Ans 27) see the pic
therefore, distance = 1/2×10×4 = 20m
Ans 26) AB shows that its acceleration is positively increading , BC shows that its acceleration is now constant and AD shows that its acceleration is 0.
Ans 27) see the pic
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