Question

Please this question in linear equation​

Answer 1

The sum of 3 consecutive multiples of 3 is 333

One multiple of 3 = 3x

The multiple of 3 after that will then be = 3(x+1)

And the third multiple will be = 3(x+2)

So,

3x + 3(x+1) + 3(x+2) = 333

3x + 3x + 3 + 3x + 6 = 333

9x + 9 = 333

9x = 333-9

9x = 324

x = 36

So, x = 36

The 3 multiples are therefore:

3x = 3*36 = 108

3(x+1) = 3*(36+1) = 3*37 = 111

3(x+2) = 3*(36+2) = 3*38 = 114

So, the 3 multiples are 108, 111 and 114

Hope this helped!

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Answer 2

Answer:

hope it will help ☺️ you .Is the solution of your question