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upper level.....
parallel combination --- 1/8 + 1/16 + 1/16= 4ohm
series combination ----- 4 + 20= 24 ohm
Now at lower level.....
parallel combination --- 1/9 + 1/18 = 6 ohm
series combination --- 6+6=12ohm
FINALLY RESISTANCE ACROSS A & B = 1/24 + 1/12 = 8ohm
best
seldon
parallel combination --- 1/8 + 1/16 + 1/16= 4ohm
series combination ----- 4 + 20= 24 ohm
Now at lower level.....
parallel combination --- 1/9 + 1/18 = 6 ohm
series combination --- 6+6=12ohm
FINALLY RESISTANCE ACROSS A & B = 1/24 + 1/12 = 8ohm
best
seldon
SeldonAngmo:
tnx so much for markin my answer as brainliest
Answered by
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First we will go for upper part
Where R1=8 ohm
R2=16
R3=16
To find resistance in || let
1/Rp=1/16+1/16+1/8
=1+1+2/16=4/16
1/Rp=1/4
Where Rp=4 ohms
Now find Re in upper portion
Re=4+20=24ohm
Now come to lower section
Where R1=9 ohm
R2= 18 ohm
Now find Rp=1/9+1/18
=2+1/18=3/18
& 3/18=1/6
Rp=6 ohm
Now Re =6+6=12ohm
Now for whole cicircuit
Rp=1/24+1/12=1+2/24ohm
=3/24ohm & 1/Rp=1/8
& Rp=8 ohm and.
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