Question

please answer question no.8 for me

Answer 1

Hey There,

Here let $-\frac{2}{3} = a$

Then your question becomes: 
$a^3 a^{-3} (-1)^{17} \\ \\ = a^3 \frac{1}{a^3} (-1) \\ \\ = \textbf{-1}$


Here, $a^3$ gets cancelled by $a^{-3}$. 
And, -1 raised to an odd power is also -1. 
That is why, your answer is -1.

Hope it helps
Purva
Brainly Community

Answer 2

HELLO.....FRIEND!!

THE ANSWER IS HERE,

$= > \: ({ \frac{ - 2}{3} )}^{3} \times ( { \frac{ - 2}{3} })^{ - 3} \times { (- 1)}^{17}$

For -2/3 Bases are equal.So, Powers must be added.


$= > \: ({ \frac{ - 2}{3} )}^{3 - 3} \times ( - 1)$

$= > \: ( { \frac{ - 2}{3} )}^{0} \times ( - 1)$

=> 1×(-1)

=> -1


:-)Hope it helps u.