Question

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Answer 1

Answer:

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Answer 2

The criteria are met, so you can integrate by using the equality u = x – 3:

Declare a variable u and substitute it into the integral:

Differentiate u = x – 3 and isolate the x term. This gives you the differential du = dx.

Substitute du for dx in the integral:

Evaluate the integral: ...

Substitute back x – 3 for u:

Hope this helps you

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