Question

please urgently help me...​

Answer 1

Step-by-step explanation:

This is in the form of f(x)^g(x) and the base tends to 1 ( since 1 + 1/infinity = 1 )

= e^{(x)(1 + 1/x - 1)}

= e^{(x)(1/x)}

= e^1

= e

HOPE IT HELPS YOU