Question

please urgently please give me ans
explain in detail​

Answer 1

As we know that

Heat q= k*A*(∆T/∆x)

so k = (q*∆x)/A*∆T

now in units, it will be

k = (Watt*meter)/meter^2*Kelvin

= Watt/(meter*Kelvin)

so dimension formula will be

$= (m {l}^{2} {t}^{ - 3} \times l) \times {l}^{ - 2} \times {k}^{ - 1} \\ = (m {l}^{1} {t}^{ - 3} {k}^{ - 1} )$

so option"A" will be the right answer.

Answer 2

Answer:

''a'' option is correct as:

Explanation:

In imperial units, thermal conductivity is measured in BTU/(h⋅ft⋅°F). The dimension of thermal conductivity is M1L1T−3Θ−1, expressed in terms of the dimensions mass (M), length (L), time (T), and temperature (Θ).

hope this helps u...

brainliest pls...