Question

The distance between the point A ( 7,4) B (3,1) is ​

Answer 1

Solution:

Let A(x1,y1) = (7,4)

B(x2, y2) = (3,1)

Distance between the points

AB = √(x2-x1)²+(y2-y1)²

= √(3-7)²+(1-4)²

= √(-4)²+(-3)²

= √16+9

= √25

= 5

Therefore,

Distance (AB) = 5 units

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Answer 2

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