Question

Please work the following question on a sheet of paper and send it’s picture

Answer 1

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Answer 2

Here Your Answer in Attachment.

Correction

$( \frac{ {x}^{a {}^{2} } }{x {}^{b {}^{2} } } ) {}^{ \frac{1}{a + b}} \times ( \frac{ {x}^{b{}^{2} } }{ {x}^{c {}^{2} } }) {}^{ \frac{1}{c + b} } \times ( \frac{ {x}^{c {}^{2} } }{ {x}^{a {}^{2 }} } ) {}^{ \frac{1}{a + c} } = 1$

As we Know According to Law of Exponent

$(x {}^{a} ) {}^{b} = {x}^{ab}$

$\frac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b}$

${x}^{a} \times {x}^{b} = {x}^{a + b}$

$x {}^{0} = 1$

1.Firstly Arrange All Terms Inside The Bracket with the Rule of Exponent.

2.Then Do Calculation work of Each Exponent.

3.Then Multiply Bracket Terms with outside term that is its power.Do this with each

4.Then According to Law of Exponent all Base will be Same Add all the powers.

5.Then you will got x^0=1

$\underline{\mathbf{\huge{Answer=1}}}$

Hence

$\underline{\mathbf{\huge{LHS=RHS✓}}}$