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In tr ABC,XZ is parallel to AB & X is midpt of BC
So, by converse of mid point theorem
Z is midpt of AC
Similarly
In tr AXC,YZ is parallel to AX & Z is midpt of AC
Yis midpt of CX
YC=1/2 XC=1/4BC
So, by converse of mid point theorem
Z is midpt of AC
Similarly
In tr AXC,YZ is parallel to AX & Z is midpt of AC
Yis midpt of CX
YC=1/2 XC=1/4BC
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