please............ye bhi...........
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Step-by-step explanation:
Draw an Altitude AE such that,
E lies on BC and
AE perpendicular to BC
In △AEB
By Pythagoras Theorem,
AB ² =AE²+EB² .....(1)
In △AED
By Pythagoras Theorem,
AD² =AE² +ED² .....(2)
From 1) and 2)
AD² =ED²+AB² −EB² .....(3)
Since, EB= 1/2BC²=AB/2=3/AB and
ED=BC/6=AB/6
∴ AD²=AB²/36 + AB² - 9AB²/36
∴ 9AD² =7AB²
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