Question

please yrr process me batana please 30 min le lo lekin kar lo nhi aata toh sorry nhi likhna second part bhejta hu follow karo follow back karuga​

Answer 1

Answer:

1.

$Answer: The \: length \: of \: third \: piece \: is \dfrac{7}{20}m \: 207m \: </p><p></p><p>Step-by-step \: explanation:</p><p></p><p>Since \: we \: have \: given \: that \: </p><p></p><p>Length \: of \: a \: piece \: of \: wire = \dfrac{3}{4}\ m \: 43 m \: </p><p></p><p>Length \: of \: first \: piece \: of \: wire = \dfrac{3}{20}\ m \: 203 m \: </p><p></p><p>Length \: of \: second \: piece \: of \: wire = \dfrac{5}{3}\times \dfrac{3}{20}=\dfrac{1}{4}\ m \: 35×203=41 m \: </p><p></p><p>Let \: the \: length \: of \: third \: piece \: of \: wire \: be \: x. \: </p><p></p><p>According \: to \: question, it \: becomes,</p><p></p><p>\begin{gathered}\dfrac{3}{20}+\dfrac{1}{4}+x=\dfrac{3}{4}\\\\\\\dfrac{3+5}{20}x=\dfrac{3}{4}\\\\\\\dfrac{8}{20}+x=\dfrac{3}{4}\\\\\\x=\dfrac{3}{4}-\dfrac{8}{20}\\\\\\x=\dfrac{15-8}{20}\ m=\dfrac{7}{20}\end{gathered}203+41+x=43203+5x=43208+x=43x=43−208x=2015−8 m=207 \: </p><p></p><p>Hence, \: the \: length \: of \: third \: piece \: is \:  \dfrac{7}{20}\ m \: 207 m</p><p></p><p>$

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