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Answer:
sum Linear pairs of angles is 180°
therefore,
(i) (6x-40)° + (5x+9)° + (3x + 15)° =180°
(6x+5x+3x) +(-40+9+15) = 180°
(14x) + (-16) = 180
x = (180+16)/14
x = 14
thus, the angles are
6(14)-40 = 44°
5(14)+9 = 79°
3(14)+15 = 57°
(ii) Here the sum of angles is 360°
therefore,
(2y+10)° + 50° + 40° + 130° = 360°
(2y+10)° + 220° = 360°
2y+10. = 360° - 220°
2y +10 = 140°
thus, the angles are
2y+10 = 140°
50°, 40° and 130°.
(1) as we know, the total degree of given diagram = 180°
( 6x - 40 )° + ( 5x + 9 )° + ( 3x + 15 )° = 180°
6x + 5x + 3x - 40 + 9 + 15 = 180°
14x - 16 = 180°
14x = 180° + 16
14x = 196
x = 196 / 14
x = 14
we put value of x in angles so,
6x - 40 = 6 ( 14) - 40 = 84 - 40 = 44
5x + 9 = 5 ( 14 ) + 9 = 70 + 9 = 79
3x + 15 = 3 ( 14 ) + 15 = 42 + 15 = 57
(2) as we know , the degree of given diagram = 360°
50° + 40° + 130° + ( 2y + 10° ) = 360°
220 + 2y + 10 = 360°
230 + 2y = 360°
2y = 360° - 230°
2y = 130°
y = 130° / 2
y = 65°
we put value of y in angle so,
2y + 10 = 2 ( 65 ) + 10 = 130 + 10 = 140°