Math, asked by syad2345, 3 months ago

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Answered by adityak4m6le007
2

Answer:

sum Linear pairs of angles is 180°

therefore,

(i) (6x-40)° + (5x+9)° + (3x + 15)° =180°

(6x+5x+3x) +(-40+9+15) = 180°

(14x) + (-16) = 180

x = (180+16)/14

x = 14

thus, the angles are

6(14)-40 = 44°

5(14)+9 = 79°

3(14)+15 = 57°

(ii) Here the sum of angles is 360°

therefore,

(2y+10)° + 50° + 40° + 130° = 360°

(2y+10)° + 220° = 360°

2y+10. = 360° - 220°

2y +10 = 140°

thus, the angles are

2y+10 = 140°

50°, 40° and 130°.

Answered by keenjal
1

(1) as we know, the total degree of given diagram = 180°

( 6x - 40 )° + ( 5x + 9 )° + ( 3x + 15 )° = 180°

6x + 5x + 3x - 40 + 9 + 15 = 180°

14x - 16 = 180°

14x = 180° + 16

14x = 196

x = 196 / 14

x = 14

we put value of x in angles so,

6x - 40 = 6 ( 14) - 40 = 84 - 40 = 44

5x + 9 = 5 ( 14 ) + 9 = 70 + 9 = 79

3x + 15 = 3 ( 14 ) + 15 = 42 + 15 = 57

(2) as we know , the degree of given diagram = 360°

50° + 40° + 130° + ( 2y + 10° ) = 360°

220 + 2y + 10 = 360°

230 + 2y = 360°

2y = 360° - 230°

2y = 130°

y = 130° / 2

y = 65°

we put value of y in angle so,

2y + 10 = 2 ( 65 ) + 10 = 130 + 10 = 140°

I hope this will be help you

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