Question

pleaseee Help DeaR fRieNds
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Answer 1

Answer:

Suppose the length of a rectangle = x cm

Suppose the breadth of a rectangle = y cm

We know that,

Area of rectangle = length * breadth

=> Area of a rectangle = xy cm^2

According to the question,

If length is increased by 10 and breadth is decreased by 5,

Area = (x+10) × (y-5)

=> xy = xy - 5x + 10y - 50

=>5x - 10y = -50 —–(1)

According to the question,

If length is decreased by 5 and breadth is increased by t,

Area = (x-5) × (y+4)

=> xy = xy + 4x - 5y - 20

=> 4x - 5y = 20 ——(2)

Lets solve equations (1) and (2) now.

Lets multiply equation (2) with 2

&

Then subtract equation (2) by equation (1),

=> (5x - 10y) - 2(4x - 5y) = -50 - 2(20)

=> 5x - 8x - 10y + 10y = - 90

=> -3x = -90

=> x = 30

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Lets put the value of x in equation (1),

=> 5x - 10y = - 50

=> 5(30) - 10y = - 50

=> 150 - 10y = - 50

=> - 10y = - 50 - 150

=> - 10y = - 200

=> y = 200/10

=> y = 20

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So the area is,

=> xy = 30 × 20

=> xy = 600 cm^2

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Length of a rectangle is 30 cm

Breadth of a rectangle is 20 cm

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Area of a rectangle is 600 cm2

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Hope My Answer Helped

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