the percentage of a father four times the age of his son after 10 years age of father will became three time the age of his son find the present age
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let the present age of son is x.
present age of father is 4x.
after 10 years,
son's age is x+10
father's age is 4x+10
After 10 years father's age is 3 times more than his son's age.
Means :father's age = 3×son's age.
(x+10)×3 = 4x+10
3x+30 = 4x+10
30-10 = 4x-3x
20 = x
x = 20
hence, the present age of son
= x = 20 years
present age of father = 4x =
4×20=80 years
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Answer:
Present age of son is 20 years and present age of father is 80 years.
Explanation:
Given :-
- The present age of a father is 4 times the age of his son.
- After 10 years, age of father will become 3 times the age of his son.
To find :-
- Their present ages.
Solution :-
Consider,
- Son's present age = x years
★ The present age of a father is 4 times the age of his son.
Then,
- Father's present age = 4x years
After 10 years,
- Father's age = (4x+10) years
- Son's age = (x+10) years
According to the question,
- After 10 years, age of father will become 3 times the age of his son.
4x+10 = 3(x+10)
→ 4x+10 = 3x+30
→ 4x-3x = 30-10
→ x = 20
Then,
★ Present age of son = 20 years
★ Present age of father = 4×20 = 80 years
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