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Hey mate !!
Here's the answer !!
So given that,
Mass of bottle = 30 g
Mass of Ethanol with bottle's mass = 78 g
So Mass of only Ethanol = 78 g - 30 g = 48 g
We know that Molar Mass of Ethanol :
Ethanol = C₂H₅OH
= 2 ( 12 ) + 5 ( 1 ) + ( 16 ) + ( 1 )
= 24 + 5 + 16 + 1
= 25 + 21
= 46 g
So Number of Moles = Given Mass / Molar Mass
=> Number of Moles = 48 g / 46 g = 1.04 Moles.
We know that,
Number of moles = Given Volume / 22.4 liters
=> 1.04 * 22.4 = Given Volume
=> 23.296 liters.
So the given volume of Ethanol is 23.296 Liters.
Now we know that Density = Mass / Volume
=> Density = 48 / 23.296 = 2.06 g / Liter
Therefore to conclude,
Mass = 48 g
Volume = 23.296 L
Density = 2.06 g / L
Hope my answer helps !!
Cheers !!
Here's the answer !!
So given that,
Mass of bottle = 30 g
Mass of Ethanol with bottle's mass = 78 g
So Mass of only Ethanol = 78 g - 30 g = 48 g
We know that Molar Mass of Ethanol :
Ethanol = C₂H₅OH
= 2 ( 12 ) + 5 ( 1 ) + ( 16 ) + ( 1 )
= 24 + 5 + 16 + 1
= 25 + 21
= 46 g
So Number of Moles = Given Mass / Molar Mass
=> Number of Moles = 48 g / 46 g = 1.04 Moles.
We know that,
Number of moles = Given Volume / 22.4 liters
=> 1.04 * 22.4 = Given Volume
=> 23.296 liters.
So the given volume of Ethanol is 23.296 Liters.
Now we know that Density = Mass / Volume
=> Density = 48 / 23.296 = 2.06 g / Liter
Therefore to conclude,
Mass = 48 g
Volume = 23.296 L
Density = 2.06 g / L
Hope my answer helps !!
Cheers !!
naju7:
ok
Answered by
9
Answer:
Thank you for free points
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