Question

Pleese solve rational and proposition ​

Answer 1

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

The percentage of men of the population of the town= 35%

The percentage of women of the population of the town= 40%

So The percentage of children of the population of the town = (100-35-40)% = 25%

Let the whole population of the town = x

So

$x \times 25 \% = 20000$

$\implies \: x \times \frac{25}{100} = 20000$

$\implies \: x \: = 20000 \times \frac{100}{25} = 80000$

So the whole population of the town = 80000

Hence the required number of women

$= 80000 \times 40 \% = 80000 \times \frac{40}{100} = 32000$

Answer 2

$\bf\huge\ Question:-$

Pleese solve rational and proposition

$\bf\huge\ Answer:-$

The percentage of men of the population of the town= 35%

The percentage of women of the population of the town= 40%

So The percentage of children of the population of the town = (100-35-40)% = 25%

Let the whole population of the town = x

So

x \times 25 \% = 20000x×25%=20000

\implies \: x \times \frac{25}{100} = 20000⟹x×

100

25

=20000

\implies \: x \: = 20000 \times \frac{100}{25} = 80000⟹x=20000×

25

100

=80000

So the whole population of the town = 80000

Hence the required number of women

= 80000 \times 40 \% = 80000 \times \frac{40}{100} = 32000=80000×40%=80000×

100

40

=32000