Question

plese answer it is urgent I will mark brainliest​

Answer 1

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→Answer:

$a_{10}=191$

Step-by-step explanation:

→ Series 1 : 3+7+11+....

The common difference is 4.

If series continues 3+7+11+15+19+23+27+31+35+39+....

→ Series 2 : 1+6+11+...

The common difference is 5.

If the series continues 1+6+11+16+21+26+31+36+41+46+51+...

The common numbers between both series are

11 , 31 , 51 , 71 , .....

So common difference = 31-11 = d=20

First term = a = 11

→ So 10 th term = $a_{10}=a+9d=11+9*20=191$

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