Math, asked by pokemanticash, 11 months ago

plese help frnds...ques7

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Answered by Anonymous
17
Heya !!

Here is your solution :

Let, that man had x money.

According to question,

First Step :

He loses 25% of total money.

Now, he has 75% of total money left.

= 75% of x

= ( 75/100 ) x

= ( 3/4 )x

= ( 3x/4 )

Second Step :

He spends 20% of rest money.

Now, he has 80% of rest money.

= 80% of ( 3x/4 )

= ( 80/100 ) ( 3x/4 )

= ( 3x/5 )

Third Step :

After all that , he has Rs. 10,200.

So,

⇒ ( 3x/5 ) = Rs. 10,200

⇒ 3x = 5 × Rs. 10,200

⇒ 3x = Rs. 51,000

⇒ x= ( Rs. 51,000 ) ÷ 3

•°• x = Rs. 17,000

Hence, the man had Rs. 17,000 originally.

Verification :

Money after losing 25% of total and spending 20% of left money = Rs. 10,200.

⇒Lost Money = 25% of total Money

⇒Lost Money = ( 25/100 ) Rs. 17,000

⇒Lost Money = ( Rs. 17,000 ) ÷ 4

•°• Lost Money = Rs. 4,250

So,

⇒ Left Money = Rs. 17,000 - Rs. 4,250

•°• Left Money = Rs. 12,750

Now,

He spends 20% of Left Money.

⇒ Money Spent = 20% of Rs. 12,750

⇒ Money Spent = ( 20/100 ) Rs. 12,750

⇒ Money Spent = ( Rs. 12,750 ) ÷ 5

•°• Money Spent = Rs. 2,550

Now,

⇒ Left Money = Rs. 12,750 - Rs. 2,550

•°• Left Money = Rs. 10,200 = Money after losing 25% and spending 20% of left Money.

Verified !!



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Answered by Shubhendu8898
2

Let the man had x rupees.

According to question he loses 25% of money he has(x). So, after losing of x he has 75% of x rupees.

Remaining Money = 75% of x

= 75\100 * x

= 3x/4

He spends 20% of remaining money. it means now he has 80% of remaining money.

According to he has 10,200 Rupees.

So,

 80 \% \  of \  \frac{3x}{4}= 10,200 \\ \\  \frac{80}{100} * \frac{3x}{4} = 10200 \\ \\ \frac{3x}{5} = 10200  \\ \\ 3x = 51000 \\ \\ x = 17,000 \  \textbf{Rupees}

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