Question

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Answer 1

We know :-

$\sf{ log_b a = c }$

$\sf{ \implies a = b^c}$

We have :-

$\sf{ log_2 x = 2.5 }$

$\sf{ x = 2^{2.5} }$

$\sf{ x = 4\sqrt{2}}$

Answer 2

Answer:

(A) 4√2

Step-by-step explanation:

w.k.t., logₐx = b can be written as aᵇ = x.

⇒ log₂x = 2.5 can be written as $2^{2.5}$ = x.

⇒ $2^{\frac{25}{10}}$ = x

⇒ $2^{\frac{5}{2}}$ = x

⇒ √32 = x

⇒ x = 4√2

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