plese solve it ,it's important
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angle abc = angle acb=40° (angle opp to equal sides of an isoceles angles are always equal)
b+c+a=180°
80+a=180
a=°
ob=oc=4.5cm ( given )
b+c+a=180°
80+a=180
a=°
ob=oc=4.5cm ( given )
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Hi, solution is here :-
a) To find - ∠BAO
∠ABC = ∠ACB ( angles opp. to equal sides are equal )
So, ∠ABC = ∠ACB = 40 °
∠A + ∠B + ∠C = 180 °
80 ° + ∠A = 180 °
So, ∠A = 100
So, ∠BAO + ∠COA = 100 °
2 ∠BAO = 100 ° ( ∠BAO = ∠COA )
∠BAO = 100 °/2
= 50 °
b) To Find - Measure of OC
OB = OC ( Triangle AOB is symmetrical to Triangle AOC )
So, OB = OC = 4.5 cm
Hope This Helps You
a) To find - ∠BAO
∠ABC = ∠ACB ( angles opp. to equal sides are equal )
So, ∠ABC = ∠ACB = 40 °
∠A + ∠B + ∠C = 180 °
80 ° + ∠A = 180 °
So, ∠A = 100
So, ∠BAO + ∠COA = 100 °
2 ∠BAO = 100 ° ( ∠BAO = ∠COA )
∠BAO = 100 °/2
= 50 °
b) To Find - Measure of OC
OB = OC ( Triangle AOB is symmetrical to Triangle AOC )
So, OB = OC = 4.5 cm
Hope This Helps You
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