Math, asked by salilraj4254, 1 year ago

pllz help me pllz find the value of k ?​

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Answers

Answered by kshtijrawat177
0

Answer:

kx(x-2)+6=0

simply open the bracket to convert it into quadric format

kx^2-2kx+6=0

a=k b=-2k c=6

now use the formulae of roots

[b^2-4AC=0] since the roots are real and equal

(-2k)^2-4(6k)=0

4k^2-24k=0

4k^2=24k

divide both sides by k

4k=24

k=24/4

k=6

ie[

Step-by-step explanation:

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