pllz help me pllz find the value of k ?
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Answer:
kx(x-2)+6=0
simply open the bracket to convert it into quadric format
kx^2-2kx+6=0
a=k b=-2k c=6
now use the formulae of roots
[b^2-4AC=0] since the roots are real and equal
(-2k)^2-4(6k)=0
4k^2-24k=0
4k^2=24k
divide both sides by k
4k=24
k=24/4
k=6
ie[
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