Question

Plot √9.3 on number line.

Answer 1

STEPS: 1: On a numberline mark AB = 9.3 unit & BC= 1 unit.

2: Mark O the mid point of AC

3: Draw a semicircle with O as centre & OA as radius

4: At B draw a perpendicular BD.

5: BD = √9.3 unit

6: Now, B as centre, BD as radius, draw an arc, meeting the numberline at E.

7: E represents √9.3

JUSTIFICATION:

BD = √ {(10.3/2)² - (8.3/2)²}

=> BD = √{10.3²- 8.3²)/4 }

=> BD = √{(10.3+8.3)(10.3–8.3)/4}

=> BD = √{18.6*2/4}

=> BF = √{37.2/4}

=> BD = √9.3 = BE

Answer 2

hi my dear friend .. here's your ans .. sorry , but i was making it thats'why i take a lot of time.. i hope this helps you.
1) Draw a line segement of about 9.3
2) then , draw 2 cm more line .
3) on point B make an angle ans then make an arc of about 90° angle.
take more than half of the line segement and draw one arc from point C and other arc from point A to find the middle point .
4) when you find the middle point then make a semi circle around it from the middle point.

if u like my answer , so plzz mark it as brainiliest..
thankyou,
yours lovingly friend,
Nevika.