Question

Plot A(0, 2), B(-2.5, 0) and C(3.5, 0) in a graph paper and find the area of ∆ ABC.​

Answer 1

Answer:

area of triangle abc =half *base*height

=1/2*(OB+OC)*OA

=1/2*(2.5+3.5)*2

=6 sq.units

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Answer 2

$\huge{\red{\underline{\mathtt{Answer}} -}} \\ { \mathtt{Area \: Of \: ∆ABC= \frac{1}{2} \times BC×AC}} \\ { \mathtt{= \frac{1}{2} \times (OB+OC)×AO}} \\ { \mathtt{= \frac{1}{2} \times (2.5 + 3.5)×2}} \\ { \mathtt{ = 6sq.unit}} \\ \\ \\ { \{\red{\underline{\mathtt{Hope \: it \: helps \: you!!}} -}}$