Question

plot the point P(6-8) and from it draw PM and PN perpendicular to X-axis and Y- axis . what are the co-ordinate of M and N​

Answer 1

Answer:

Step-by-step explanation:

R.E.F image  

ar(ABCD)=ar(ABC)+ar(ACD)

for Δ(ADC)

Use heron's formula

S=  

2

15+12+9

​  

=18cm

ar(ABC)=  

S(S−a)(S−b)(S−c)

​  

 

ar(ABC)=  

18×3×6×9

​  

=54cm

||ly for Δ(ACB)

S=  

2

15+12+7

​  

=17

ar(ABC)=  

17×(17−15)(17−12)(17−7)

​  

=10  

17

​  

cm  

2

 

​  

 

⇒  

ar(ABCD)=(10  

17

​  

+54)cm  

2

 

hope it will help you

Answer 2

Answer :-

• The co-ordinate of M are (6,0)
• The co-ordinate of N are (0,-8)

Step-by-step explanation:

To Find :-

• The co-ordinate of M
• The co-ordinate of N

Given,

• The point given = P (6,-8)
• PM and PN are drawn perpendicular to X-axis and Y-axis.

Solution:

• The required answer. [ Refer the attachment, Given ]

Know more :-

• In 1st, 2nd, 3rd and 4th quadrants, the co-ordinates of the points are (+,+); (-,+); (-,-) and (+,-).

• The co-ordinate of any point on x-axis is of the form (x,0).

• The co-ordinate of any point on y-axis is of the form (0,y).

• Each point in a plane is represented by an ordered pair (a,b), where a is the x-coordinate and b is the y-coordinate of the point.