Question

Plot the points A(0, 0), B(3, 0); C(3, 3) and
DO, 3) on graph paper. Show that ABCD is a square.
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Answer 1

Answer:

Step-by-step explanation:

distance between AB = square root (0-3)^ + (0-0)^

square root (-3)^ + 0

square root  9 = 3

distance between AB = 3 units

distance between BC = square root (3-3)^+(0-3)^

square root 0+-3^

square root  9 = 3

distance between BC = 3 units

distance between CD = square root (3-0)^ + (3-3)^

square root 3^ + 0

square root 9 = 3

distance between  CD = 3 units

distance between AD = square root (0-0)^+(0-3)^

square root 0+-3^

square root 9=3

distance between AD = 3 units

in square all sides are equal

distance between AC = 3 root 2

distance between BD = 3 root 2

therefore the diagonals are equal in a square

therefore ABCD is a square

thus, it is proved