Question

Plot the points A(0,0), B(4,-2), C(8,0) and D(4,2).Join this points in the given order.Show that BD is the perpendicular
type of quadrilateral is ABCD?

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Answer 1

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Answer 2

Answer:

Properties of Rhombus:

1)Diagonal Bisect each other at 90°

here in the given figure Diagonal AC and BD meet at point E.

Here length of AC is 6; EC= EA =3 unit

Here length of BD is 4; BE= ED =2 unit

both the axis x and y meet at origin and perpendicular to each other.

So, ABCD is a rhombus.

1) Equation of AC => y=0

2)Equation of BD=> x=0