Math, asked by gaury27, 9 months ago

Plot the points A(7,0), B(2,5), C(7,5), D(5,3), E(2,3), F(2,-2), G(4,-4), H(-4,-4), I (-2,-2), J(-2,3), K(-5,3), L(-7,5), M(-2,5). Join them in order(A to B to C and so on)

Find the areas of the triangle ABM, Trapeziums (BCDE, FGHI, JKLM), and rectangle MBFI.

Hence find the total area of the figure so formed

Answers

Answered by amitnrw
0

Given :  points A(0,7), B(2,5), C(7,5), D(5,3), E(2,3), F(2,-2), G(4,-4), H(-4,-4), I (-2,-2), J(-2,3), K(-5,3), L(-7,5), M(-2,5).

To find :  areas of the triangle ABM, Trapeziums (BCDE, FGHI, JKLM), and rectangle MBFI.

Solution:

triangle ABM,    BM is the base = 4   (= 2 -(-2))     Height = 2  = ( 7 - 5)

Area = (1/2)*4*2  = 4 sq units

Area of Trapeziums  BCDE   , BC = 5  DE = 3   , BE ( height) = 2

Area = (1/2)(5 + 3) * 2 = 8 sq units

Area of Trapeziums FGHI   , FI = 4  GH = 8   ,  ( height) = 2

Area = (1/2)(4 + 8) * 2 = 12 sq units

Area of Trapeziums  JKLM   , JK = 3  LM = 5   , JM ( height) = 2

Area = (1/2)(5 + 3) * 2 = 8 sq units

rectangle MBFI.   MB = 4  BF =  7

Area = 4 * 7 = 28 sq units

Total area =  4 + 8 + 12 + 8  + 28  = 60 sq units

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