Plot y=3x/2+2/3 on a graph
Answers
Answer:
Explanation:
First, this equation is in slope-intercept form. The slope-intercept form of a linear equation is:
y
=
m
x
+
b
Where
m
is the slope and
b
is the y-intercept value.
y
=
3
x
−
2
Or
y
=
3
x
+
−
2
Therefore, we know the slope is:
m
=
3
And the
y
-intercept is:
b
=
−
2
or
(
0
,
−
2
)
We can start graphing this equation by plotting the
y
-intercept:
graph{(x^2 + (y+2)^2 - 0.025) = 0 [-10, 10, -5, 5]}
Slope is defined as
rise
run
, or the amount the
y
value changes compared to the
x
value.
The slope for this equation is
m
=
3
or
m
=
1
.
Therefore for each change in
y
of
3
,
x
changes by
1
.
We can now plot another point using this information:
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Now, we can draw a straight line through the two points to graph the equation:
graph{(y - 3x +2)(x^2 + (y+2)^2 - 0.025)((x - 1)^2 + (y - 1)^2 - 0.025) = 0 [-10, 10, -5, 5]}