Question

Plot y=3x/2+2/3 on a graph​

Answer 1

Answer:

Explanation:

First, this equation is in slope-intercept form. The slope-intercept form of a linear equation is:

y

=

m

x

+

b

Where

m

is the slope and

b

is the y-intercept value.

y

=

3

x

−

2

Or

y

=

3

x

+

−

2

Therefore, we know the slope is:

m

=

3

And the

y

-intercept is:

b

=

−

2

or

(

0

,

−

2

)

We can start graphing this equation by plotting the

y

-intercept:

graph{(x^2 + (y+2)^2 - 0.025) = 0 [-10, 10, -5, 5]}

Slope is defined as

rise

run

, or the amount the

y

value changes compared to the

x

value.

The slope for this equation is

m

=

3

or

m

=

1

.

Therefore for each change in

y

of

3

,

x

changes by

1

.

We can now plot another point using this information:

enter image source here

Now, we can draw a straight line through the two points to graph the equation:

graph{(y - 3x +2)(x^2 + (y+2)^2 - 0.025)((x - 1)^2 + (y - 1)^2 - 0.025) = 0 [-10, 10, -5, 5]}