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in figure d is a point on bc such that
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Answered by
1
ab2=ac2+bc2
25=9+bc
bc2=25-9
bc=
=4
Answered by
56
ɧɛყą ɱąɬɛ ɧɛཞɛ ıʂ ųཞ ąŋʂῳɛཞ
by pythagoras theorem in ΔACD
AD^2=AC^2+DC^2
4^2=3^2+DC^2
16=9+DC^2
√7=DC
IN ABCAB^2=BC^2+AC^2
5^2=3^2+BC^2
25=9+BC^2
4=BC
AREA(ACD):AREA(BCA)
AC^2:BC^2
3^2:4^2
9:16
ɧơ℘ɛ ıɬ ɧɛƖ℘ʂ
by pythagoras theorem in ΔACD
AD^2=AC^2+DC^2
4^2=3^2+DC^2
16=9+DC^2
√7=DC
IN ABCAB^2=BC^2+AC^2
5^2=3^2+BC^2
25=9+BC^2
4=BC
AREA(ACD):AREA(BCA)
AC^2:BC^2
3^2:4^2
9:16
ɧơ℘ɛ ıɬ ɧɛƖ℘ʂ
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