Chemistry, asked by pchatti82, 11 months ago

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Answered by karunyareddy
0

Answer:

4

Explanation:

lets assume the concentration of c as 2x and d as also 2x due to equilibrium

now on lhs Their concentration will be x.

kc=2x*2x/x*x

kc=4

Answered by ammu1279
0
equilibrium constant is a chemical reaction is the value of its reaction quotient at equilibrium a state approached by A dynamic chemical system after sufficient time has elapsed at which its composition has measurable tendency towards further change

let us take concentration of C as a and D as 2a

kc= 2a*2a/a*a


kc = 4


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