Question

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Answer 1

The sum of the percentage of carbon, hydrogen, and chlorine is not 100 %

Hence the rest of the part of the compound is oxygen

percentage of oxygen =100(18.6+1.55+55.04)=24.81%$

Simplest ratio =1:1:1:1

Hence empirical formula =CHCIOCHCIO

Empiraical formula weight =12×1+1×1+35.5×1+16×1=64.5=12×1+1×1+35.5×1+16×1=64.5

n= molecular mass empirical mass=12964.5n= molecular mass empirical mass=12964.5=2=2

Therefore molecular formula = n ××Empirical formula

Molecular formula = 2×(CHCIO)2×(CHCIO)

Molecular formula C2H2Cl2O2C2H2Cl2O2

But the acid is monobasic acid, hence it should contain one -COOH group

i.e the molecular formula of organicmonobasic acid is CHCl2COOH

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