Question

pls. ans. my Q from Q 6 .​

Answer 1

$Answer \: \\ \\ Given \: \: Quadratic \: polynomial \: \: is \: \\ \\ ax {}^{2} - 5x + c \\ \\ let \: its \: two \: zeros \: be \: \: \alpha \: \: \: and \: \: \: \beta \\ \\ \alpha + \beta = \frac{5}{a} \: \: \: \: and \: \: \: \: \alpha \beta = \frac{c}{a} \\ \\ According \: to \: the \: given \: question \\ \\ \alpha + \beta = \alpha \beta = 10 \\ \\ \frac{5}{a} = 10 \: \: \: \: \: \: \frac{c}{a} = 10 \\ \\ \\ a = \frac{5}{10} \: \: \: \: \: \: and \: \: \: c = 10a \\ \\ a = \frac{1}{2} \: \: \: \: and \: \: \: c = 10 \times \frac{1}{2} = 5 \\ \\ therefore \: \: \: \: a = \frac{1}{2} \: \: \: \: \: and \: \: \: \: c \: 5 \\ \\ NOTE \: \\ \\ for \: general \: Quadratic \: polynomial \: \: say \\ p(x) = ax {}^{2} + bx + c \\ \\ \alpha + \beta = \frac{ - b}{a} \: \: \: \: \: \: and \: \: \: \: \alpha \beta = \frac{c}{a}$

Answer 2

Answer:

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so your solution is

ax^2-5x+c=0

Step-by-step explanation:

sum of zeores =-b/a

-(-5)/a= 10

a= 1/2

thus.

product =c/a

c/a=10 and a=1/2 so

c= 5

hope it will help you

thankns.....