Math, asked by aditya4374683137, 3 months ago

Pls Ans the above question of algebra​

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Answered by bibizainab8597
0

Answer:

LS is not equal to RS

Step-by-step explanation:

When s=0, 4s+9 = 4(0)+9 = 9, value of LS=9, here LS is not equal to RS.

When s=1, 4s+9 = 4(1)+9 = 13, value of LS=13, here LS is not equal to RS.

When s=2, 4s+9 = 4(2)+9 = 17, value of LS=17, here LS is not equal to RS.

When s=3, 4s+9 = 4(3)+9 = 21, value of LS=21, here LS is not equal to RS.

When s=4, 4s+9 = 4(4)+9 = 25, value of LS=25, here LS is not equal to RS.

When s=5, 4s+9 = 4(5)+9 = 29, value of LS=29, here LS is not equal to RS.

When s=6, 4s+9 = 4(6)+9 = 33, value of LS=33, here LS is not equal to RS.

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