pls ans this guys pls
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let's make theta=x (for ease of typing in)
(sinx)/(1+cosx)
multiply numerator & denominator with (1-cosx)
=(sinx)*(1-cosx)/ (1+cosx)(1-cosx)
=sinx(1-cosx)/ (1-cos^2x)
=sinx(1-cosx)/ sin^2x {since cos^2x+sin^2x =1}
=(1-cosx)/sinx
Hence proved
let's make theta=x (for ease of typing in)
(sinx)/(1+cosx)
multiply numerator & denominator with (1-cosx)
=(sinx)*(1-cosx)/ (1+cosx)(1-cosx)
=sinx(1-cosx)/ (1-cos^2x)
=sinx(1-cosx)/ sin^2x {since cos^2x+sin^2x =1}
=(1-cosx)/sinx
Hence proved
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