pls ans this guys pls
Attachments:
Answers
Answered by
0
Best Answer
let's make theta=x (for ease of typing in)
(sinx)/(1+cosx)
multiply numerator & denominator with (1-cosx)
=(sinx)*(1-cosx)/ (1+cosx)(1-cosx)
=sinx(1-cosx)/ (1-cos^2x)
=sinx(1-cosx)/ sin^2x {since cos^2x+sin^2x =1}
=(1-cosx)/sinx
Hence proved
let's make theta=x (for ease of typing in)
(sinx)/(1+cosx)
multiply numerator & denominator with (1-cosx)
=(sinx)*(1-cosx)/ (1+cosx)(1-cosx)
=sinx(1-cosx)/ (1-cos^2x)
=sinx(1-cosx)/ sin^2x {since cos^2x+sin^2x =1}
=(1-cosx)/sinx
Hence proved
Similar questions