Math, asked by meghna200646, 1 year ago

pls ans this question​

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Answered by Anonymous
6

 {x}^{x \sqrt{x} }  = (x \sqrt{x} ) \\  \\  =  >  {x}^{x. {x}^{ \frac{1}{2} } }  = x. {x}^{ \frac{1}{2} }  \\  \\  =  >  {x}^{ {x}^{ \frac{3}{2} } }  =  {x}^{ \frac{3}{2} }  \\  \\  on \: comparing \:  \\  \\  =  >  {x}^{ \frac{3}{2} }  =  \frac{3}{2}  \\  \\  on \: sqaring \: both \: the \: side \:  \\  \\  =  >  {x}^{3}  =  \frac{9}{4}  \\  \\  =  > x =  \sqrt[3]{ \frac{9}{4} }


shanaya1437: hii
Anonymous: Yes
shanaya1437: ur name??
meghna200646: Neelormi
shanaya1437: ....XD
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