Question

pls ans to be brainlist

Answer 1

I've marked the vertices on the figure itself....A, B and C

Answer 2

Hey Mate !!

Here is your solution :

For, 4x - y = 4

=> 4x - y = 4

=> 4x - 4 = y

=> 4( x - 1 ) = y

Let , x = 1.

=> 4( 1 - 1 ) = y

=> 4 ( 0 ) = y

=> 0 = y

= A( 1 , 0 )

Let , x = 2.

=> 4 ( x - 1 ) = y

=> 4 ( 2 - 1 ) = y

=> 4 ( 1 ) = y

=> 4 = y

= B( 2 , 4 )

Solution for this eq. : A( 1 , 0 ) ; B( 2 , 4 ).

Now,

For , ( 4x + y = 12 )

=> 4x + y = 12

=> y = 12 - 4x

=> y = 4( 3 - x )

Let , x = 3

=> y = 4( 3 - 3 )

=> y = 4 × 0

=> y = 0

= C( 3 , 0 )

Let , x = 2

=> y = 4( 3 - x )

=> y = 4( 3 - 2 )

=> y = 4 × 1

=> y = 4

= D( 2 , 4 )

Solution for this eq. = C( 3 , 0 ) ; D( 2 , 4 ).

Graph : Go through the attachment.

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Hope it helps !! ^_^