Math, asked by adhilkp09, 1 year ago

Pls answer ... 11
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Answered by SnackReaper
1

n^2-m^2= (sin^2Acos^2B-cos^2Asin^2B)/sin^2Bcos^2B  sin^2x=1-cos^2x (n^2-m^2)sin^2B=cos^2B-cos^2Acos^2B-cos^2A+cos^2Acos^2B/cos^2B = cos^2B-cos^2A/cos^2B =1-m^2

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