Question

pls answer 22b
step by step explanation

Answer 1

let side of square be a

then a²=144

=>. a=12cm

now length of wire =perimeter of square=4 x 12

hence length of wire =48 cm

so, let side of eql. triangle be x

then perimeter of eql. triangle=length of wire

=> 3x=48

=> x= 16cm

now,area of eql. triangle=

$\frac{ \sqrt{3} \times {x}^{2} }{4} \\ = \frac{ \sqrt{3} \times 256 }{4} \\ = \sqrt{3 } \times 64 \\ = 64 \sqrt{3} {cm}^{2}$