Question

Pls answer all the questions

Answer 1

(1)

Amount= Rs 8625

Principle (p) = Rs 7500

Rate (r) = 7 1/2%pa = 15/2 %

Simple Interest(si) = Amount – Principle

SI = Rs 8625- Rs 7500

SI = Rs 1125

We know that the formula for simple interest

SI = (p × r × t)/100

Substitute the given values in the above equation we get,

1125 = (7500 × t × 15/2)/ 100

The simple interest equation becomes

1125 = (7500 × t × 15)/200

225000 = 112500 × t

t = 2 years

Hence the time required to pay ₹7500 amount to ₹8625, if interest is reckoned at 7 1/2<%pa is 2 years.

(2)

The amount is given as Rs4320 and the principle is given as Rs3600 with the rate of 4%. Then, the simple interest will be,

S.I.=Amount−Principle

=4320−3600 =720

Now,

S.I. = (P×R×T)/100

720 = (3600×4×T)/100

T= (720×100)/(3600×4)

T=5years

(3)

The principle is given as Rs6300 and the simple interest is given as Rs2100 with time as 4 years.

S.I.= (P×R×T)/100

2100 = (6300×R×4)/100

R= (2100×100)/(6300×4)

R=8.34%

(4)

Principal,P = Rs. 66,000

Time,T = 2 years

S.I. = 72,720 - 66,000 = Rs. 6,720

Rate,R = ?

∴ S.I. = (P×R×T)/100

⇒ R = ( 6720×100 )/(66,000×2)

⇒ Rate = 5.09% per annum

(5)

Let Rs x be the sum. Then according to the question, the simple interest will be 3x/5.

S.I.= (P×R×T)/100

3x/5 = (x×R×5)/100

R= (3x×100)/(5×x×5)

R=12%

(6)

The simple interest is given as Rs829.50 with the rate of 10% per annum for 3 years.

Using same Formula as (5)

829.50 = (P×10×3)/100

P = (829.50×100)/(10×3)

P = Rs. 2765

(7)

This question is same as (6) , you have to find P.

Put the value of SI, R & T and find P.

Try to solve it yourself.

Answer 2

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