Question

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Answer 1

Question

If sum of squares of zeroes of quadratic polynomial 6x² + x + k is 25/36, the value of k is?

Answer:-

-2

Step by step answer

$ \blue{ \implies} $ Compare given expression with ax²+bx+c a=6,b=1,c=k let zeroes of polynomials are a and B

sum of the zeroes =a+ß= -b/a= -1/6 ----(1) product of the roots =aß= c/a = k/6----(2)

given sum of the squares of zeroes

=25/36 a²+p²= 25/36---(3)

do the square both sides of (1)

(a+ß)²=(-1/6)² a²+3²+2aß-1/36

25/36+2aß-1/36[from (3)]

2aß-1/36-25/36

2a3=(1-25)/36 2aß=-24/36

aß= -24/2*36

aß=-1/3---(4)

but (2) =(4)

k/6 = -1/3

k= (-1/3) *6

k=-2

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