Question

pls answer
by steps pls​

Answer 1

Answer:

I hope its helpful for you

Step-by-step explanation:

mark me as branliests

Answer 2

a) $\frac{4}{x-3}$ + $\frac{2}{x-2}$ = $\frac{6}{x}$

$\frac{4(x-2+2(x-3)}{(x-3)(x-2)}$ = $\frac{6}{x}$

$\frac{4x-8+2x-6}{x^{2} -3x-2x+6 }$ = $\frac{6}{x}$

$\frac{6x-14}{x^{2} -5x+6}$ = $\frac{6}{x}$

x(6x - 14) = 6(x² -5x +6)

6x² - 14x = 6x² - 30x +36

6x² - 14x - 6x² + 30x = 36

16x = 36

x = $\frac{36}{16}$

x = $\frac{9}{4}$

b) $\frac{(y-4)}{5}$ + $\frac{(y+2)}{2}$ = 10

$\frac{2(y-4)+5(y+2)}{10}$ = 10

$\frac{2y-8+5y+10}{10}$ = 10

$\frac{7y+2}{10}$   = 10

7y + 2 = 10 × 10

7y+2 = 100

7y = 100 - 2

7y = 98

y = 98 ÷ 7

y = 14  

hope it helps!

have a great day!