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Answer:(a) Calcium hydroxide solution in the test tube B becomes milky.
(b) Reaction in test tube A:2CH3COOH + Na2CO3 → 2CH3COONa + H2O + CO2 Ca(OH)2 + CO2 → CaCO3 + H2O (Test tube B) With excess CO2, milkiness disappears. CaCO3 + H2O + CO2 → Ca(HCO3)2
(c) As C2H5OH and Na2CO3 do not react, a similar change is not expectedC2H5OH + Na2CO3 → No change
(d) The lime water is prepared by dissolving calcium oxide in water and decanting the supernatent liquid.
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