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Class 11................
A man holds his umbrella vertically upward while walking due west with a constant velocity of magnitude v = 1.5 m/s in rain. To protect himself from rain, he has to rotate his umbrella through an angle Θ = 30° when he stops walking. Find the velocity of the rain.
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When the man is at rest w.r.t ground, the rain is coming to him at an angle of 30 degree with the vertical.
Velocity of rain w.r.t ground=Vr
Velocity of man w.r.t ground=Vm=1.5 m/s
Velocity of rain w.r.t man=Vrm
From the figure,
sin 300=1.5Vror Vr=1.5sin 300=3 m/sAgain,tan300=1.5Vrpor Vrm=1.5tan300=1.5×3=2.6 m/s
Velocity of rain w.r.t ground=Vr
Velocity of man w.r.t ground=Vm=1.5 m/s
Velocity of rain w.r.t man=Vrm
From the figure,
sin 300=1.5Vror Vr=1.5sin 300=3 m/sAgain,tan300=1.5Vrpor Vrm=1.5tan300=1.5×3=2.6 m/s
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Anonymous:
the answer is 3 m/s
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