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Let the ten’s digit be x
Let the unit’s digit be y
Let the original number be 10x+y
Let reversed number be 10y+x
X=5y
X-5y=0.............eqn 1
(10x+y)+(10y+x)=66
11x+11y=66
11(x+y=6)
Therefore x+y=6..........eqn 2
Solving simultaneously
x-5y=0
x+y=6
Multiplying 2nd eqn by -1
x-5y=0
-x-y=-6
x and -x strike off and we begets the remaining
-6y=-6
therefore y=1
Substituting the value of y in eqn....1
x-5y=0
x-5=0
x=5
Original Number =10x+y
=50+1
=51..........Final Answer
Let the unit’s digit be y
Let the original number be 10x+y
Let reversed number be 10y+x
X=5y
X-5y=0.............eqn 1
(10x+y)+(10y+x)=66
11x+11y=66
11(x+y=6)
Therefore x+y=6..........eqn 2
Solving simultaneously
x-5y=0
x+y=6
Multiplying 2nd eqn by -1
x-5y=0
-x-y=-6
x and -x strike off and we begets the remaining
-6y=-6
therefore y=1
Substituting the value of y in eqn....1
x-5y=0
x-5=0
x=5
Original Number =10x+y
=50+1
=51..........Final Answer
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